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Your answer A boxer punches a sheet of paper in midair, and brings it from rest up to a speed of 40 m/s in 0.05 s. If the mass of the paper is 0.01 kg, what is the force of impact on the paper?
Your answer A boxer punches a sheet of paper in midair, and brings it from rest up to a speed of 40 m/s in 0.05 s. If the mass of the paper is 0.01 kg, what is the force of impact on the paper?
Answer:Force of impact, F = 8 NExplanation:It is given that,Mass of the paper, m = 0.01 kgInitial speed of the paper, u = 0Final speed of the paper, v = 40 m/sTime taken, t = 0.05 sFirstly finding the acceleration of the paper using the equation of kinematics as :Let F is the force of impact on the paper. It is equal to the product of mass and the acceleration as :F = 8 NSo, the force of impact on the paper is 8 N. Hence, this is the required solution....
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