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Write a balanced chemical equation based on the following description: Solid lead(IV) chlorite decomposes to form solid lead(IV) chloride and oxygen gas. a) 2Pb(ClO2)4 → 2PbCl4 + O2 b) Pb(ClO2)4 → PbCl4 + O2 c) Pb(ClO2)4 → PbCl4 + 2O2 d) 2Pb(ClO2)4 → PbCl4 + 2O2
Write a balanced chemical equation based on the following description: Solid lead(IV) chlorite decomposes to form solid lead(IV) chloride and oxygen gas. a) 2Pb(ClO2)4 → 2PbCl4 + O2 b) Pb(ClO2)4 → PbCl4 + O2 c) Pb(ClO2)4 → PbCl4 + 2O2 d) 2Pb(ClO2)4 → PbCl4 + 2O2
Final answer:In the decomposition of solid lead(IV) chlorite into solid lead(IV) chloride and oxygen gas, the correct balanced chemical equation is a) 2Pb(ClO2)4 → 2PbCl4 + O2. Always make sure to check both sides of the equation to account for each atom.Explanation:In Chemistry, the process of breaking down a compound to form others, like our scenario here, is called decomposition. Your question is about the decomposition of lead(IV)chlorite into lead(IV) chloride and oxygen gas.Considering full conservation of matter, we need our equation to be balanced. Let's consider our options:a) 2Pb(ClO2)4 → 2PbCl4 + O2b) Pb(ClO2)4 → PbCl4 + O2c) Pb(ClO2)4 → PbCl4 + 2O2d) 2Pb(ClO2)4 → PbCl4 + 2O2The correct answer is option A. In other cases, you need to check both sides of the equation to account for each atom. If the atoms do not match, adjust using coefficients.Learn more about Balanced Chemical Equation here:brainly.com/question/34199830#SPJ11...