Final answer:The hybridization at the boron atom in gaseous BBr3 is (C) sp², resulting in a trigonal planar molecular geometry.Explanation:The hybridization at the boron atom in gaseous BBr3 is (C) sp². In molecules where boron is the central atom and forms three covalent bonds without any lone pairs of electrons, the boron atom undergoes sp² hybridization. Boron has one 2s and three 2p valence orbitals.When involved in three bonds, only two of the 2p orbitals and the 2s orbital mix to formthree sp² hybridized orbitals, while the third 2p orbital remains unhybridized. This results in a trigonal planar structure, similar to the observed structure in borane (BH3).Learn more about Boron Hybridization here:brainly.com/question/41245606#SPJ11...

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