Applying thetrigonometric ratios, the missing sides and angles of theright trianglesare:1. x = 7.32. x = 33.33. x = 21.34. x = 31.95. x = 25.66. x = 11.07. x = 41.8°8. x = 64.2°9. x = 12.8°10. x = 51.3°Trigonometry RatiosThetrigonometry ratiosfor solvingright trianglesare:SOH: sin ∅ = opp/hypCAH: cos ∅ = adj/hypTOA: tan ∅ = opp/adj.1. ∅ = 63°hyp = 16adj = x = ?ApplyCAH:cos 63 = x/16x =  cos 63 × 16x = 7.32. ∅ = 39°opp = 27adj = x = ?ApplyTOA:tan 39 = 27/xx =  27/tan 39x = 33.33. ∅ = 49°adj = 14hyp = x = ?ApplyCAH:cos 49 = 14/xx = 14/cos 49x = 21.34. ∅ = 15°hyp = 33adj = x = ?ApplyCAH:cos 15 = x/33x =  cos 15 × 33x = 31.95. ∅ = 52°adj = 20opp = x = ?ApplyTOA:tan 52 = x/20x =  tan 52 × 20x = 25.66. ∅ = 27°opp = 5hyp = x = ?ApplySOH:sin 27 = 5/xx = 5/sin 27x = 11.07. ∅ = x°hyp = 6opp = 4ApplySOH:sin x = 4/6x = sin^-1(4/6)x = 41.8°8. ∅ = x°adj = 14opp = 29ApplyTOA:tan x = 29/14x = tan^-1(29/14)x = 64.2°9. ∅ = x°hyp = 54opp = 12ApplySOH:sin x = 12/54x = sin^-1(12/54)x = 12.8°10. ∅ = x°hyp = 40adj = 25ApplyCAH:cos x = 25/40x = cos^-1(25/40)x = 51.3°Learn more abouttrigonometric ratioson:brainly.com/question/10417664...

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