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Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of water. Water is being added to the first pool at a rate of 27 liters per minute. Water is being added to the second pool at a rate of 39 liters per minute. (a) For each pool, write an expression for the amount of water in each pool after x months. (b) Write an equation to show when the two pools would have the same amount of water.
Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of water. Water is being added to the first pool at a rate of 27 liters per minute. Water is being added to the second pool at a rate of 39 liters per minute. (a) For each pool, write an expression for the amount of water in each pool after x months. (b) Write an equation to show when the two pools would have the same amount of water.
Answer:a)Total amount of water in pool 1 after x minutes = 1850+27xTotal amount of water in pool 2 after x minutes = 1334+39xb) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39xStep-by-step explanation:First Pool :Initial amount of water in Pool = 1850 litersWater is being added to the first pool at a rate of 27 liters per minute.Amount of water added after x minutes = 27xSo, Total amount of water after x minutes = 1850+27xSecond Pool:Initial amount of water in Pool = 1334 litersWater is being added to the first pool at a rate of 39 liters per minute.Amount of water added after x minutes = 39xSo, Total amount of water after x minutes = 1334+39xNow to find an equation to show when the two pools would have the same amount of water.1850+27x= 1334+39x1850-1334=39x-27x516=12x43 =xHencea)Total amount of water in pool 1 after x minutes = 1850+27xTotal amount of water in pool 2 after x minutes = 1334+39xb) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x...