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Thetimebefore they are 1870feetapart is mathematically given asX=6minWhat is the time before they are 1870feet apart?Question Parameters:Two old RSM students were standing 10 feet apartat the speeds of 150 feet per minutethey are 1870feet apartGenerally, thetimethey areapartis mathematically given asX=final distance apart/speeds of runThereforeX=1870/(150+160)X=6minIn conclusion,time before they are 1870feet apartX=6minRead more aboutwidthbrainly.com/question/2096451...