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Two large parallel metal plates are 1.5 cm apart and have charges of equal magnitudes but opposite signs on their facing sur- faces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then ????5.0 V, what is the electric field in the region between the plates?
Two large parallel metal plates are 1.5 cm apart and have charges of equal magnitudes but opposite signs on their facing sur- faces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then ????5.0 V, what is the electric field in the region between the plates?
Final answer:The electric field between the two plates, given a potential of -5.0 V at the midpoint, is 666.67 V/m, directed from the positive plate towards the negative.Explanation:The question revolves around finding the electric field between two large parallel metal plates with charges of equal magnitude but opposite signs. Given the potential at the midpoint between the plates is -5.0 V and taking the potential of the negative plate as zero, we can calculate the electric field (E) in the region between the plates. Since the potential difference (V) is directly proportional to the distance (d) in the uniform electric field, we use the formula E = V/d.In this case, the distance (d) from the midpoint to either of the plates is 0.75 cm (half of 1.5 cm). Hence, with a potential difference of 5.0 V at the midpoint, the electric field E can be calculated as: E = 5.0 V / 0.0075 m = 666.67 V/m.This electric field is directed from the positive plate towards the negative plate, due to the way electric fields are defined (from positive to negative)....