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The Reaction at A: RA = 11,917 lbsThe Reaction at D: RD = 8,083 lbsThe Deflection at C is ΔC = 0.0142 inAt point A and D, where the rods are fixed, draw arrows pointing inwards representing the reaction forces acting on the rods from the supports. These forces are not known and we call them RA and RDThe reaction at A:A_AC = π/4 * (1 in² = 0.785 in²A_CD = π/4 * (1/2 in)² = 0.196 in²The compatibility equation:(RA * 10 in) / (0.785 in² *psi) + ((RA-20000 lbs) * 8 in) / (0.196 in² *psi) = 0We then Solve for RA:In the horizontal direction, the sum of forces must equal zero:RA + RD - P = 0RA = 11,917 lbs.Solve for RD:RD = P - RA = 20000 lbs - 11917 lbs= 8083 lbsDeflection at C, take note we are using rod CDΔC = (RD * 10 in) / (A_CD * E_s)= (8083 lbs * 10 in) / (0.196 in² *psi)= 0.0142 in...