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Two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of 412 N, and the other has a weight of 908 N. The rope and the pulleys are massless and there is no friction.
Two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of 412 N, and the other has a weight of 908 N. The rope and the pulleys are massless and there is no friction. (a) What is the acceleration of the lighter block?
(b) Suppose that the heavier block is removed, and a downward force of 908 N is provided by someone pulling on the rope, as part b of the drawing shows. Find the acceleration of the remaining block.
(c) Explain why the answers in (a) and (b) are different.
Answergiven,Weight of one block = m₁ = 412 NWeight of other block = m₂ = 908 Npulley is mass less and have no frictiona) acceleration of lighter blockT - m₁g = m₁aT - 412 = m₁a..............(1)m₂g - T = m₂a908 - T = m₂a..............(2)adding equating equation (1) and (2)496 = (m₁ + m₂)aa = 3.68 m/s²b) downward force of 908 N is provided need to calculate acceleration of remaining blocknow,F - mg = maa = 11.79 m/s²c) there is difference in the result because in part b force is applied to move the smaller weight.but in part a, both of the masses are independent to move....
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