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(b) Suppose that the heavier block is removed, and a downward force of 908 N is provided by someone pulling on the rope, as part b of the drawing shows. Find the acceleration of the remaining block.

(c) Explain why the answers in (a) and (b) are different.

Answergiven,Weight of one block = m₁ = 412 NWeight of other block = m₂ = 908 Npulley is mass less and have no frictiona) acceleration of lighter blockT - m₁g = m₁aT - 412 = m₁a..............(1)m₂g - T = m₂a908 - T = m₂a..............(2)adding equating equation (1) and (2)496 = (m₁ + m₂)aa = 3.68 m/s²b) downward force of 908 N is provided need to calculate acceleration of remaining blocknow,F - mg = maa = 11.79 m/s²c) there is difference in the result because in part b force is applied to move the smaller weight.but in part a, both of the masses are independent to move....

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