Final answer:To create three different challenging equations that each equal 100, one can use different combinations of mathematical operations and concepts, such as addition with multiplication, exponents, and fractions.Explanation:Finding three different challenging math equations that each equal 100 can be a great exercise in problem solving and algebra. Here are three examples:Using a combination of addition and multiplication: 90 + 5 × 2 = 100. Start with 90, then multiply 5 by 2, which gives 10, and finally add 90 and 10 to get 100.Involving exponents and square roots: 10^2 = 100. This is because raising 10 to the power of 2 means you multiply 10 by itself once, which results in 100.Working with fractions: (1/2) × 200 = 100. Here, you're taking one half of 200, which of course gives you 100.In each case, you're employing different arithmetic operations or mathematical concepts to arrive at the same result, which is 100. These examples can better help students understand the flexibility of mathematics and how different operations interact....

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