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• there are approximately 3,000,000,000 base pairs in the mammalian genome (genes constitute only a small portion of this total)
• there are approximately 3,000,000,000 base pairs in the mammalian genome (genes constitute only a small portion of this total)• there are approximately 10,000 genes in the mammalian genome
• a single gene averages about 10,000 base pairs in size
Questions
1. Based on the assumptions above, in the mammalian genome, how many total base pairs are in all the mammalian genes?
2. What percentage (%) of the total genome does this represent?
3. What is the chance (%) that a random mutation will occur in any given gene?
4. Only 1 out of 3 mutations that occur in a gene result in a change to the protein structure. What is the probability that a random mutation will change the structure of a protein?
3,000,000,000 base pairs10,000 genes10,000 base pairs per gene1) number of base pairs are in all the mammalian == number base pares in each gene*number of genes=10,000 *10,000=1,000,000,0002) 1,000,000,000 is 1/3 of 3,000,000,000because 1,000,000,000/3,000,000,000 = 1/3which is about 0.33which is the same as 33/100which means it is33%3) A random mutation has33%probability to occur in a gene (the same as the proportion bp gene/bp genome as asked in 2))4) You have to multiply both probabilities: 1/3*1/3=1/9 = 0.11 = 11/100 =11%...
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