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The load P required to displace the roller downward 0.2 mm is approximately 48,000 N.The total axial stiffness (k) of the truss can be calculated as the sum of the axial stiffness of each member:k = 3 * (E * A) / LWe can use the following equation, which relates the load (P), the stiffness (k), and the displacement (delta):delta = P / kP = k * deltaSubstituting the known values:P = (3 * 200e9 Pa * 400e-6 m^2) / 1 m * 0.2e-3 mP ≈ 48000 NTherefore, the load P required to displace the roller downward 0.2 mm is approximately 48,000 N....