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the scores on a collegiate mathematics readiness assessment are approximately normally distributed with a mean of 680 and a standard deviation of 120. determine the percentage of scores between 690 and 900, to the nearest percent.
the scores on a collegiate mathematics readiness assessment are approximately normally distributed with a mean of 680 and a standard deviation of 120. determine the percentage of scores between 690 and 900, to the nearest percent.
43.36% of thescoresfall between 690 and 900 on the collegiate mathematics readinessassessment.To determine thepercentageof scores between 690 and 900, we need to calculate the area under the normal distribution curve between these two values.First, we need to standardize the scores using the formula z = (x - μ) / σ, where x is the score, μ is the mean, and σ is thestandard deviation.For the score 690:z1 = (690 - 680) / 120 = 0.0833For the score 900:z2 = (900 - 680) / 120 = 1.8333Next, we need to find the area between these two standardized scores. We can use a standard normal distribution table or a statistical calculator to find the corresponding probabilities.From the standardnormal distributiontable, we find that the area to the left of z1 is approximately 0.5328 and the area to the left of z2 is approximately 0.9664.To find the area between z1 and z2, we subtract the smaller area from the larger area:Area = 0.9664 - 0.5328 = 0.4336Finally, we convert the area to a percentage by multiplying by 100:Percentage = 0.4336 * 100 ≈ 43.36%Therefore, approximately 43% of the scores fall between 690 and 900 on the collegiate mathematics readiness assessment.Know more aboutpercentagehere:brainly.com/question/24877689#SPJ8...