Final answer:Thehybridizationof the lead atom in PbCl4 is dsp3, which is characterized by the combination of one 5d orbital, one 6s orbital, and three 6p orbitals from the lead atom.Explanation:The hybridization of thelead atomin PbCl4 is dsp3. Hybridization is essentially the mixing of atomic orbitals to form new, hybrid orbitals. In case of PbCl4, the Lead (Pb) atom is thecentral atom. Theelectronic configurationof Pb is [Xe] 4f14 5d10 6s2 6p2. When it forms PbCl4, it loses its two 6s electrons and accepts electrons from the four Cl atoms. So, in this process, it uses a 6s orbital, three 6p orbitals, and one 5d orbital. This gives us a total of 5orbitals, which is why the hybridization is dsp3.Learn more about Hybridization here:brainly.com/question/32068264#SPJ11...

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