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The enzyme amylase can break glycosidic linkages between glucose monomers only if the monomers are the α form. Which of the following could amylase break down?

The enzyme amylase can break glycosidic linkages between glucose monomers only if the monomers are the α form. Which of the following could amylase break down? a) glycogen, starch, and amylopectin
b) glycogen and cellulose
c) cellulose and chitin
d) starch and chitin
e) starch, amylopectin, and cellulose

Answer:a) glycogen, starch, and amylopectin.Explanation:Amylasecan only break polymers which haveα glycosidic linkagesbetweenglucose monomers. Starch, glycogen and amylopectin they all are α polymers of glucose. Their description is mentioned as under:Starch:Amylose & amylopectin are 2 forms of starch. Amylose is ahelicalandunbranchedpolymer of glucose withα ( 1 → 4) linkage. ~ 15 % of starch exists in amylose form.Amylopectin:Amylopectin is a form of starch but it is branched and it has 2 types of linkagesα ( 1 → 4) linkage&α ( 1 → 6) linkage. Almost 80-85 % of starch exists in this form.Glycogen:Glycogen is somehow similar to that of amylopectin with the only difference that it has more branching as compared to amylopectin.Rest of the options include polymers which haveβ linkagelike chitin & cellulose so those options are wrong....

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