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The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 1. 7 μc, and the distance between them is d = 1. 9 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings
The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 1. 7 μc, and the distance between them is d = 1. 9 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings
1. Thenet forceon 2 in the first drawing is 02. The net force on 2 in the second drawing is 2737.8 N3. The net force on 2 in the third drawing is 1935.9 NWhat is coulomb's law?Coulomb's lawstates that the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.F = kQq/r²K = 9 × 10⁹For the first drawingforce between 1 and 2F = 9 × 10⁹ × 17² ×/19×F = -1368.9 NForce between 2 and 3= + 1368.9NTherefore,1. thenet forcein the first drawing is 0and2. the net force in the second drawing will beF1 = +1368.9 and F2 = +1368.9Net force = 1368.9 + 1368.9= 2737.8 N3. The netforce in the third drawing will be obtained by using Pythagorean theoremF = √ 1368.9² + 1368.9²F = √3747774.4F = 1935.9 Nlearn more aboutcoulombs lawfrombrainly.com/question/26892767#SPJ1...