TeH2 is the chemical formula for tellurium hydride.To determine the number of valence electrons inTeH2, we need to consider the valence electrons of tellurium (Te) and hydrogen (H),tellurium is in group 16 of theperiodictable, so it has 6 valence electrons. Hydrogen is in group 1, so it has 1 valence electron. In TeH2, there are 2 hydrogen atoms bonded to 1 tellurium atom. Therefore, the total number of valence electrons in TeH2 is 6 + (2 x 1) = 8 valence electrons.Now let's draw the Lewis structure for TeH2. we place the tellurium atom in the center and surround it with hydrogen atoms. Eachhydrogenatom is connected to the tellurium atom with a single bond.we distribute the remaining valenceelectronsaround the atoms to satisfy the octet rule. Since there are 8 valence electrons in total, we place 2 electrons as a lone pair on the tellurium atom. This leaves us with 6 electrons to distribute around the hydrogen atoms. Each hydrogen atom needs 2 electrons to complete its octet, so we pair up the remaining 6 electrons as 3 lone pairs on each hydrogen atom. The final Lewis structure for TeH2 looks like this,H:Te:HEach hydrogen atom is connected to the tellurium atom with a single bond, and eachatomhas 2 lone pairs of electrons around it.To know more aboutTeH2visit:brainly.com/question/32398629#SPJ11...

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