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Supply the missing quantities.
Supply the missing quantities.Figure
Description
A tree diagram has two stages. Stage 1 has two nodes and stage 2 has four nodes.
In stage 1, the branch from the starting position to node A is labeled 0.4. The branch from the starting position to node B is an answer blank.
In stage 2, the branch from node A to node C is an answer blank. The branch from node A to node D is labeled 0.6.
In stage 2, the branch from node B to node C is labeled 0.1. The branch from node B to node D is an answer blank.
Outcome
P(A ∩ C) =
P(A ∩ D) =
P(B ∩ C) =
P(B ∩ D) =
Final answer:The missingprobabilitiesin the tree diagram are found using the principle that probabilities of branches from a single node sum up to 1. The intersections are found by multiplying the probabilities of the respective nodes.Explanation:The question is about finding the missingprobabilitiesin a tree diagram. In a tree diagram, the sum of the branches out from a single node equals 1. You can use this fact to find missing quantities:Stage 1: The branch from the starting position to node B can be found by subtracting the probability of the branch to node A (0.4) from 1. So, the answer is 1 - 0.4 = 0.6.Stage 2: The branch from node A to node C can be found by subtracting the probability of the branch to node D (0.6) from 1. So, the answer is 1 - 0.6 = 0.4. The branch from node B to node D can be found by subtracting the probability of the branch to node C (0.1) from 1. So, the answer is 1 - 0.1 = 0.9.Outcome : We can now find the intersections by multiplying:P(A ∩ C) = 0.4 * 0.4 = 0.16,P(A ∩ D) = 0.4 * 0.6 = 0.24,P(B ∩ C) = 0.6 * 0.1 = 0.06, andP(B ∩ D) = 0.6 * 0.9 = 0.54.Learn more about Tree Diagram Probabilities here:brainly.com/question/32663440#SPJ1...