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Theheattransferred to and the work produced by thesteamduring this process is 13781.618 kJ/kgHow to calcultae the heat?TheNet Changein Enthalpy will be:= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kgWork Done(Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)= 1/2 x ( 75 + 225) x (5 - 2)W = 450 KJFrom the First Law ofThermodynamics, Q = U + WSo,HeatTransfer = Change in Internal Energy + Work Done= 13331.618 + 450Q = 13781.618 kJ/kgLearn more aboutheaton:brainly.com/question/13439286#SP1...