Final Answer:SiBr4 has a tetrahedralmolecular geometrywith sp3 hybridization, bond angles of approximately 109.5 degrees, and is a polar molecule.Explanation:SiBr4, or silicontetrabromide, consists of a silicon atom bonded to four bromine atoms. The Lewis structure shows a central silicon atom with four surrounding bromine atoms. Each bromine forms a single bond with the silicon, resulting in a tetrahedral molecular geometry. This geometry arises from the arrangement that minimizes electron repulsion.In terms of hybridization, the silicon atom undergoes sp3 hybridization. This means that the fourvalence electronsof silicon are rearranged into four hybrid orbitals, allowing for the formation of four sigma bonds with the four bromine atoms.The bond angles in SiBr4 are approximately 109.5 degrees. This is a characteristic of tetrahedral geometry, where the angle between any two adjacent bonds is about 109.5 degrees.SiBr4 is a polar molecule. This is because the bromine atoms are more electronegative than silicon, leading to a partial negative charge on the bromine atoms and apartial positive chargeon the silicon atom. The uneven distribution of charge results in a net dipole moment, making the molecule polar.Learn more aboutmolecular geometrybrainly.com/question/31984103#SPJ11...

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