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Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain. How many half-lives transpired during this time period? half-lives Answer = Blank 1:
Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain. How many half-lives transpired during this time period? half-lives Answer = Blank 1:
The number ofhalf-livesthat transpired during thistimeperiod is equal to2.5 hours.Given the following data:Time = 12.5 hours.Initial mass = 64 grams.Remaining mass = 2.0 grams.How to determine the number of half-lives.Mathematically, the amount of a radiocativeelementthat isremainingaftertime(t-hours) is given by this formula:Where:A is theamountremaining.Ao is theinitial amount.H is thehalf-life.t is thetime.Substituting the given parameters into the formula, we have;ln(2/64) = ln(1/2) × 12.5/H-3.466 = -0.693 × 12.5/HH = 12.5 × -0.693/-3.466H = 12.5 × 0.1999H=2.5 hours.Read more onhalf-lifehere:brainly.com/question/25750315...
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