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Q4.10. A large population of land turtles on an isolated island has two alleles for a gene that determines shell thickness. The allele for thinner shells is dominant over the allele for thicker shells. The thinner-shell allele occurs at a frequency of 20%. Assuming there is no net advantage to thick or thin shells, what should the frequency of homozygous thicker-shelled turtles be in the population? (Hint: Use a population Punnett square to calculate the answer.) 4%16%50%
Q4.10. A large population of land turtles on an isolated island has two alleles for a gene that determines shell thickness. The allele for thinner shells is dominant over the allele for thicker shells. The thinner-shell allele occurs at a frequency of 20%. Assuming there is no net advantage to thick or thin shells, what should the frequency of homozygous thicker-shelled turtles be in the population? (Hint: Use a population Punnett square to calculate the answer.) 4%16%50%
Final answer:By applying the Hardy-Weinbergequilibriumequation to the given allele frequencies, the estimated frequency of homozygous thicker-shelled turtles in the population is 64%.Explanation:The frequency of thehomozygousthicker-shelled turtles can be calculated using the Hardy-Weinberg equilibrium equation p² + 2pq + q² = 1. According to the question, the allele for thinner shells (let's denote it as 'p') occurs at a frequency of 20%. Therefore, the allele for thicker shells (let's represent by 'q') occurs at a frequency of 80% or 0.8. In Hardy-Weinberg equilibrium, q² represents the frequency of homozygous recessive individuals. So, to calculate the frequency of homozygous thicker-shelled turtles, we calculate the square of q (0.8), which yields 0.64 or 64%.Note: This assumes no evolutionary forces are acting on the population, i.e., no mutation, migration, or selection, and the population is infinitely large, randomly mating, and producing offspring in equal proportions.Learn more about Hardy-Weinberg equilibrium here:brainly.com/question/16823644#SPJ2...