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ByPythagorean theorem, the calculatedhypotenuseof the right triangle 17 is 9√2 cm (approx. 12.7 cm / 127.3 mm or 12.73 cm). The difference of the answers is 3 mm. The measure is accurate.How to perform a recursive procedure with Pythagorean theoremIn this question we find a table representing arecursive algorithminvolvingPythagorean theorem, whose definition is introduced below:c² = a² + b²Where:a, b - Legs of the right triangle.c - Hypotenuse of the right triangle.Now we proceed to determine thehypotenuseof the right triangle 17:Step 1a = 3 cm, b = 3 cmc = √[(3 cm)² + (3 cm)²]c = 3√2 cmStep 2a = 3√2 cm, b = 3 cmc = √[(3√2 cm)² + (3 cm)²]c = √27 cmc = 3√3 cmStep 3a = 3√3 cm, b = 3 cmc = √[(3√3 cm)² + (3 cm)²]c = √36 cmc = 6 cmStep 4a = 6 cm, b = 3 cmc = √[(6 cm)² + (3 cm)²]c = √45 cmc = 3√5 cmStep 5a = 3√5 cm, b = 3 cmc = √[(3√5 cm)² + (3 cm)²]c = √54 cmc = 3√6 cmStep 6a = 3√6 cm, b = 3 cmc = √[(3√6 cm)² + (3 cm)²]c = √63 cmc = 3√7 cmStep 7a = 3√7 cm, b = 3 cmc = √[(3√7 cm)² + (3 cm)²]c = √72 cmc = 3√8 cmc = 6√2 cmStep 8a = 3√8 cm, b = 3 cmc = √[(3√8 cm)² + (3 cm)²]c = √81 cmc = 9 cmStep 9a = 9 cm, b = 3 cmc = √[(9 cm)² + (3 cm)²]c = √90 cmc = 3√10 cmStep 10a = 3√10 cm, b = 3 cmc = √[(3√10 cm)² + (3 cm)²]c = √99 cmc = 3√11 cmStep 11a = 3√11 cm, b = 3 cmc = √[(3√11 cm)² + (3 cm)²]c = √108 cmc = 6√3 cmStep 12a = 6√3 cm, b = 3 cmc = √[(6√3 cm)² + (3 cm)²]c = 3√13 cmStep 13a = 3√13 cm, b = 3 cmc = √[(3√13 cm)² + (3 cm)²]c = 3√14 cmStep 14a = 3√14 cm, b = 3 cmc = √[(3√14 cm)² + (3 cm)²]c = 3√15 cmStep 15a = 3√15 cm, b = 3 cmc = √[(3√15 cm)² + (3 cm)²]c = 12 cmStep 16a = 12 cm, b = 3 cmc = √[(12 cm)² + (3 cm)²]c = 3√17 cmCase 17a = 3√17 cm, b = 3 cmc = √[(3√17 cm)² + (3 cm)²]c = 9√2 cmThe calculatedhypotenuseof the right triangle 17 is equal to a length of 9√2 cm (approx. 12.7 cm or 127.3 mm, which is 12.73 cm). The difference of the answers is 3 mm.To learn more onPythagorean theorem:brainly.com/question/20254433#SPJ1...