Solved:
Answered by AI, Verified by Human Experts
Pool players often pride themselves on their ability to impart a large speed to a pool ball. In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue). With the rail removed, a ball can fly off the table, as shown in the figure. Vo = The surface of the pool table is h = 0.710 m from the floor. The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s). If the winner's ball landed a distance of d = 4.15 m from the table's edge, calculate the speed of his break shot vo. Assume friction is negligible. 10.91 At what speed v₁ did his pool ball hit the ground? V₁ = 10.93 h Incorrect d m/s m/s
Pool players often pride themselves on their ability to impart a large speed to a pool ball. In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue). With the rail removed, a ball can fly off the table, as shown in the figure. Vo = The surface of the pool table is h = 0.710 m from the floor. The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s). If the winner's ball landed a distance of d = 4.15 m from the table's edge, calculate the speed of his break shot vo. Assume friction is negligible. 10.91 At what speed v₁ did his pool ball hit the ground? V₁ = 10.93 h Incorrect d m/s m/s
Thespeedat which theballhit the ground (v₁) is approximately 11.02 m/s.How to calculate speed?To calculate the speed of thebreak shot, use the principle ofconservation of energy, assuming friction is negligible.Given:Heightof the table surface from the floor (h) = 0.710 mDistance from thetable's edgeto where the ball landed (d) = 4.15 mWorld speed record for the break shot = 32 mph (about 14.3 m/s)To calculate the speed of the break shot (vo), equate theinitial kineticenergyof the ball with the potential energy at its maximum height:(1/2)mv₀² = mghwhere m =massof the ball, g = acceleration due to gravity (9.8 m/s²), and h = height of the table surface.Solving for v₀:v₀ = √(2gh)Substituting the given values:v₀ = √(2 × 9.8 × 0.710) m/sv₀ ≈ 9.80 m/sSo, the speed of the break shot (vo) is approximately 9.80 m/s.Sincefriction is negligible, the horizontal component of the velocity remains constant throughout the motion. Therefore:v₁ = d / twhere t = time taken by the ball to reach the ground.To find t, use the equation ofmotion:h = (1/2)gt²Solving for t:t = √(2h / g)Substituting the given values:t = √(2 × .710 / 9.8) st ≈ 0.376 sSubstituting the values of d and t, now calculate v₁:v₁ = 4.15 m / 0.376 sv₁ ≈ 11.02 m/sTherefore, the speed at which the ball hit the ground (v₁) is approximately 11.02 m/s.Find out more onspeedhere:brainly.com/question/13943409#SPJ4...