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!!!PLEASE HELP!!! Trigonometry Maze Version 2: Missing Angle Measures

!!!PLEASE HELP!!! Trigonometry Maze Version 2: Missing Angle Measures

We want to solve the Trigonometry Maze.So we need to remember somerules:Sin(θ) = (opposite cathetus)/(hypotenuse)Cos(θ) = (adjacent cathetus)/(hypotenuse)Tan(θ) = (opposite cathetus)/(adjacent cathetus).Using the correspondentinverse functionswe get:θ = Asin( (opposite cathetus)/(hypotenuse) )θ = Acos( (adjacent cathetus)/(hypotenuse) )θ = Atan( (opposite cathetus)/(adjacent cathetus) )Using theseruleswe just need to see which sides are given (with respect to the angle we want to find) and use the correspondent one.For example, for the first triangle we want to find x and we know the two catheti, then we use the tangent equation.x = Atan(25/16) =57.4°So we go up left.x = Acos(29/31) =20.7°We go down.x = Atan(8/6) =53.1°We go down again.x = Asin(13/45) =16.8°We go to the right.x = Asin(25/28) =63.2°We go to the right.x = Acos(9/29) =71.9°We go up.x = Acos(14/18) =38.9°We go up.x = Atan(32/57) =29.3°We go down-right.x = Asin(24/30) =53.1°We go down.x = Acos(8/21) =67.7°We go down.x = Atan(28/45) =31.9°We go left.x = Atan(23/26)  =41.5°We go left.x = Acos(18/53) =70.1°We go left and reach theend.So following that you can solve the puzzle.If you want to learn more, you can read:brainly.com/question/15669589...

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