Final answer:The order of decreasing metallic character amongSn, Sb, Te, I is Sn > Sb > Te > I.This is because Sn is a metal, Sb and Te are metalloids with some metallic character, and I is a non-metal.Explanation:In the periodic table, elements are organized with increasing atomic number from left to right. As we move from left to right across a period, the metallic character of the elements generally decreases. Thus, to answer your question, the elements requested should be placed in the following order of decreasing metallic character:Sn (Tin), Sb (Antimony), Te (Tellurium), I (Iodine).Sn, or Tin, is a metal belonging to group 14 of theperiodic table. Sb (Antimony) and Te (Tellurium) are considered metalloids, they exhibit properties of both metals and non-metals. Iodine (I) belongs to group 17 and is a non-metal. Therefore, in terms of their metallic character:Sn > Sb > Te > I.Learn more about Metallic Character here:brainly.com/question/32758331#SPJ11...

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