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Two Half Cell reactions are as follow,3e⁻ + Al⁺³ → Al (Reduction Reaction)Mg → Mg⁺² + 2e⁻ (Oxidation Reaction)In order to balance the number of electrons, multiply reduction reaction by 2 and oxidation reaction by 3.So,6e⁻ + 2 Al⁺³ → 2 Al3 Mg → 3 Mg⁺² + 6e⁻ (e⁻ cancelled)_______________________2 Al⁺³ + 3 Mg → 2 Al + 3 Mg⁺²Result:At AnodeMagnesium metal is Oxidized andAt CathodeAluminium Ions are reduced....