Solved:
Answered by AI, Verified by Human Experts
on earth, two parts of a space probe weigh 11 000 n and 3400 n. these parts are separated by a center-to-center distance of 12 m and may be treated as uniform spherical objects. find the magnitude of the gravitational force that each part exerts on the other out in space, far from any other objects.
on earth, two parts of a space probe weigh 11 000 n and 3400 n. these parts are separated by a center-to-center distance of 12 m and may be treated as uniform spherical objects. find the magnitude of the gravitational force that each part exerts on the other out in space, far from any other objects.
Thegravitational forcethat exerts on the outer out in spaceis 1.73 ×N.Gravitational force:The force of gravity or gravitational force pulls objects with mass towards each other. The gravitational force between two objects can be calculated as a function of the product of their masses (M and m), the square of the distance between them(r), and the universal gravitational constant.Theformulais:F = G Mm/r²Let us assume that g = 10 m/s².M = 11000/ 10 = 1100kgm = 3400/10 = 340kgThe distance was given:r = 12mWe can look up a value of G:G = 6.674 ×m³ / kgs²F = 6.674( 1100 × 340)/ 12²= 17333.86 ×= 1.73×NThereforethe gravitational force is 1.73 ×N.To know more aboutgravitational attractionrefer to the link given below:brainly.com/question/15090289#SPJ4...