Answer:For a:The edge length of the unit cell is 314 pmFor b:The radius of the molybdenum atom is 135.9 pmExplanation:For a:To calculate the edge length for given density of metal, we use the equation:where,= density =Z = number of atom in unit cell = 2  (BCC)M = atomic mass of metal (molybdenum) = 95.94 g/mol= Avogadro's number =a = edge length of unit cell =?Putting values in above equation, we get:Conversion factor used:Hence, the edge length of the unit cell is 314 pmFor b:To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:where,R = radius of the lattice = ?a = edge length = 314 pmPutting values in above equation, we get:Hence, the radius of the molybdenum atom is 135.9 pm...

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