Theempirical formulafor a compound with an assumed 40% carbon and 60% oxygen would be CO. This is calculated by assuming you have 100g of the substance, then converting the grams into moles. Finally, the smallest number of moles is used to find the simplest whole number ratio.The empirical formula represents the simplestwhole-number ratioof atoms in a compound. Due to the lack of exact percentages of carbon and oxygen in the question, I will use general assumptions. Let's assume there is 40% carbon and 60% oxygen.First, change thepercentageto grams (assuming you have 100g of compound), which gives you: 40g Carbon and 60g Oxygen. Then, convert these amounts into moles: 40g Carbon / 12.01 g/mol ≈ 3.33 mol and 60g Oxygen / 16.00 g/mol ≈ 3.75 mol.Finally, divide each amount by the smallest number ofmolesto find the ratio: Carbon = 3.33 / 3.33 = 1, Oxygen = 3.75 / 3.33 ≈1.13. Since, we need a whole number ratio, let's round it off to the nearest whole number i.e., Carbon 1 : Oxygen 1. Hence, the empirical formula is CO.For more such questions onempirical formula, click on:brainly.com/question/32125056#SPJ11...

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