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Answer:[OH⁻] → 1×10⁻¹⁰Explanation:pH = - log [H⁺]pOH = - log [OH⁻]pH + pOH = 144 + pOH = 1414 - 4 = 10 → pOH10^-pOH = [OH⁻]10⁻¹⁰ = [OH⁻] → 1×10⁻¹⁰...
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