Solved:

Checkmark

Answered by AI, Verified by Human Experts

Indicate whether or not each of the structures is considered to be aromatic. Both compounds are six atom rings arbitrarily numbered starting from the top and moving clockwise. Both have a carbon in position 1 that is bonded to an N H 2 where the nitrogen has a lone pair. Carbon 1 is double bonded to nitrogen in position two. This nitrogen has a lone pair. Position 3 is a carbon that is double bonded to an oxygen and the oxygen has two lone pairs. Position 5 and 6 is an alkene. Both compounds have a nitrogen in position 4, but the nitrogen in compound A is bonded to one methyl and has a lone pair on the nitrogen, whereas the nitrogen in compound B is bonded to two methyls and has a positive charge. Which is true

Indicate whether or not each of the structures is considered to be aromatic. Both compounds are six atom rings arbitrarily numbered starting from the top and moving clockwise. Both have a carbon in position 1 that is bonded to an N H 2 where the nitrogen has a lone pair. Carbon 1 is double bonded to nitrogen in position two. This nitrogen has a lone pair. Position 3 is a carbon that is double bonded to an oxygen and the oxygen has two lone pairs. Position 5 and 6 is an alkene. Both compounds have a nitrogen in position 4, but the nitrogen in compound A is bonded to one methyl and has a lone pair on the nitrogen, whereas the nitrogen in compound B is bonded to two methyls and has a positive charge. Which is true

Final answer:Both Compound A and Compound B are considered aromatic as they both fulfillHuckel's Rule of aromaticity. The positive charge on nitrogen in Compound B does not affect its aromaticity because its lone pair of electrons is not part of the conjugated π electron system.Explanation:Compound A and B are both aromatic due to the fulfillment of Huckel's Rule. This rule states that an aromatic compound must have an uninterrupted cyclic cloud of electrons above and below the molecular plane. It should also have (4n+2) π electrons (where n is zero or any positive integer). In both compounds, we can trace a loop that includes six π electrons which satisfies Huckel's Rule thereby making these compounds aromatic. However, the positive charge on nitrogen in compound B has no significant effect on its aromaticity because thenitrogen's lone pairof electrons is not part of the conjugated π electron system.Learn more about Aromaticity here:brainly.com/question/30171805#SPJ11...

Unlock full access for 72 hours, watch your grades skyrocket.
For just $0.99 cents, get access to the powerful quizwhiz chrome extension that automatically solves your homework using AI. Subscription renews at $5.99/week.