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The providedfunctionf : {a,b,c,d} → {1,2,3} given by f = {(a, 3), (6, 1), (c, 2), (d, 3)} is one-to-one.False.A function is considered one-to-one (also known asinjective) if each element in thedomainmaps to a unique element in the codomain. In other words, no two distinct elements in the domain aremappedto the same element in the codomain.In the givenfunction, we can see that both 'a' and 'd' are mapped to the same element '3' in thecodomain{1, 2, 3}. This violates the condition of being one-to-one since two different elements in the domain are being mapped to the same element in the codomain.Therefore, the statement isFalse.Learn more aboutFunctionsclick;brainly.com/question/30721594#SPJ4...