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Answer:75 %Explanation:If we take the genotype of both parents who are both heterozygous, the resulting cross would be:Hh x HhPunnett square:H hH HH Hhh Hh hhAs you can see thre are 3 possible genotypes and 2 phentypes:HH 1 Cloven hoovesHh 2 Cloven hooveshh 1 Mule hoovesBecause cloven hooves is dominant, it will be expressed even with the presence of the recessive allele.So the probability is 3 out 4 or75%...