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In part (a) of the figure an electron is shot directly away from a uniformly charged plastic sheet, at speed vs = 3.30 × 105 m/s. The sheet is nonconducting, flat, and very large. Part (b) of the figure gives the electron's vertical velocity component v versus time t until the return to the launch point. What is the sheet's surface charge density? Assume ts = 12.0 ps.
In part (a) of the figure an electron is shot directly away from a uniformly charged plastic sheet, at speed vs = 3.30 × 105 m/s. The sheet is nonconducting, flat, and very large. Part (b) of the figure gives the electron's vertical velocity component v versus time t until the return to the launch point. What is the sheet's surface charge density? Assume ts = 12.0 ps.
the surface charge density σ is zero.Given:- Initial velocity in the vertical direction, u = 0 m/s- Final velocity in the vertical direction, v = 0 m/s (since the electron returns to the launch point)- Time taken for the electron to return to the launch point, t = 26.0 × 10^-12 sUsing the kinematic equation v = u + at, where u = 0, we can find the acceleration a in the vertical direction:v = ata = v / ta = 0 m/s^2Now, we know that the force acting on the electron is solely due to the electric field created by the sheet. The force F is given by F = qE, where q is the charge of the electron.Using Newton's second law F = ma, we can write:qE = m × 0E = 0This implies that the electric field acting on the electron is zero.The electric field E produced by a uniformly charged sheet is given by:E = σ / (2 * ε₀)Since E = 0, we can't directly determine σ from this equation. However, we can infer that the charge density σ must be such that it cancels out the electric field due to the sheet at the position of the electron.Given that the electric field at the position of the electron is zero, it means that the surface charge density σ must also be zero. This implies that the sheet does not have any net charge on its surface. Therefore, the surface charge density σ is zero.The probable question maybe:In part (a) of the figure an electron is shot directly away from a uniformly charged plastic sheet, at speed Vs = 3.90 x 10 m/s. The sheet is nonconducting, flat, and very large. Part (b) of the figure gives the electron's vertical velocity component v versus time tuntil the return to the launch point. What is the sheet's surface charge density? Assume ts = 26.0 ps. V (S/U 01) -e + + -V, t(ps) (6) (a) Number i Units C/m^2...