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in a coffee-cup calorimeter, 50.0 ml of 0.100 m agno3 and 50.0 ml of 0.100 m hcl are mixed to yield the following reaction: ag1 1aq2 1 cl2 1aq2 h agcl1s2 the two solutions were initially at 22.608c, and the final temperature is 23.408c. calculate the heat that accompanies this reaction in kj/mol of agcl formed. assume that the combined solution has a mass of 100.0 g and a specific heat capacity of 4.18 j/8c ? g.
in a coffee-cup calorimeter, 50.0 ml of 0.100 m agno3 and 50.0 ml of 0.100 m hcl are mixed to yield the following reaction: ag1 1aq2 1 cl2 1aq2 h agcl1s2 the two solutions were initially at 22.608c, and the final temperature is 23.408c. calculate the heat that accompanies this reaction in kj/mol of agcl formed. assume that the combined solution has a mass of 100.0 g and a specific heat capacity of 4.18 j/8c ? g.
Final answer:The heat thataccompaniesthe reaction in the coffee-cup calorimeter, when 50.0 ml of 0.100 m AgNO3 and 50.0 ml of 0.100 m HCl react to form AgCl, assuming that thecombined solutionhas a mass of 100.0 g and a specific heat capacity of 4.18 J/g°C, is -66.88 kJ/mol.Explanation:The heat of the reaction in acoffee-cup calorimetercan be calculated using the equation q = mcΔt, where q is the heat absorbed or released, m is the mass of the system (in this case, the combined solution with a mass of 100 g), c is the specific heat capacity (4.18 J/ °C.g), and Δt is thechange in temperature(final temperature – initial temperature = 23.408 °C - 22.608 °C = 0.8 °C).The total heat released in the reaction can be calculated as q = (100.0 g) × (4.18 J/g°C) × (0.8 °C), which gives a result of 334.4 J. Since 1 kJ = 1000 J, so we can convert that to kJ, gives 0.3344 kJ.Next, you need to calculate the number of moles of AgCl formed in the reaction. Since the molarity (M) is moles/liter and volume (V) is given in ml, you can convert volume into liters (50 ml = 0.050 L). As M = moles/L, so the number of moles = M x V = 0.100 M * 0.050 L = 0.005 moles.The heat per mole of AgCl is then (0.3344 kJ) ÷ (0.005 moles) = 66.88 kJ/mol. Therefore, the heat that accompanies the reaction in kJ/mol of AgCl formed is -66.88 kJ/mol. The negative sign indicates that the reaction is exothermic,meaning heat is released.Learn more aboutCalculating Heat of Reactionhere:brainly.com/question/24759029#SPJ11...