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If you were to take an elevator from the ground floor, where youweight469N, to the top of the building, your weight would shift by -0.237 N.Theequation for accelerationin this case is;a = GM/r²Where;G is gravitational constant = 6.67 × 10⁻¹¹ m³/kg.s²M is mass of earth = 5.972 × 10²⁴ kgr isdistancefrom center of earthSince we are trying to find change in weight, let us first find the change in acceleration with respect to r;da/dr = -2GM/r³da = -(2GM/r³) drThus, change in weight from top to bottom is;W_top - W_bottom = m(da)Now, weight at bottom is gotten from the formula;W_bottom = GmM/r²Also, W_bottom = m(da) since we are dealing with change in weight.Thus;m(da)= -(2GmM/r³) drRecall that GmM/r². Thus;m(da) = -2W_bottom × dr/rwhere;W_bottom = 469 Nr is radius of earth = 6371000 mdr = 1 mile = 1609.34 mThus;m(da) = -2 × 469 × 1609.34/6371000m(da) = -0.237 NTo know more aboutweightvisit:brainly.com/question/10069252#SPJ4...

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