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Imagine discovering three different bacterial species on a meteorite. Each species contains genetic material that is not DNA, but the genetic material of each species contains four bases. Each species has a different number of amino acids. Use the total number of amino acids per species to determine the minimum codon length for each species.
Imagine discovering three different bacterial species on a meteorite. Each species contains genetic material that is not DNA, but the genetic material of each species contains four bases. Each species has a different number of amino acids. Use the total number of amino acids per species to determine the minimum codon length for each species.
The minimumcodon length for each species are ;Specie A= 1 codon lengthFor Specie B =3 codon lengthFor specie C= 4 codon lengthGiven dataThree different bacterial species ( Species A, B and C )Each containsgenetic materialsnot DNAEach contains different number ofamino acids;Specie A = 2 amino acids ,Specie B = 56 amino acids,( missing values )Specie C = 162 amino acidsEachgenetic materialcontains four ( 4 ) basesCalculate theminimum codon lengthof each species using the total number of amino acidsFor Specie A;number of base = 4amino acids = 2∴minimum codon length = 1( due to redundancy )For Specie Bnumber of bases = 4amino acids = 56∴minimum codon length = 3Because 3 base codon is needed to code 56 amino acids ( i.e. 4^3 > 56 amino acids )For Specie Cnumber of bases = 4amino acids = 162∴minimum codon length = 4Because 4 codon is needed to code 162 amino acids ( i.e 4^4 > 162 amino acids )Hence we can conclude that the minimumcodon length for each species are ;Specie A= 1 codon length For Specie B =3 codon length For specie C= 4 codon length.Learn more :brainly.com/question/19426841...