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If a vehicle's speed doubles from 20 mph to 40 mph, the distance needed to stop the vehicle increases by ___ times. a) 2 b) 3 c) 4 d) 8. c) 4
If a vehicle's speed doubles from 20 mph to 40 mph, the distance needed to stop the vehicle increases by ___ times. a) 2 b) 3 c) 4 d) 8. c) 4
Theaverage reaction distanceis around 1 second at 20 mph. Let's say that the distance covered by thevehiclein 1 second is 8 meters. Therefore, the reaction distance is 8 meters.Braking distance is the distance the vehicle travels from the time the driver applies the brakes until the time the vehicle comes to a complete stop. This distance is affected by many factors such as road conditions, tire conditions, and the condition of the brakes. On dry roads, the average braking distance is around 4 times the speed of the vehicle in meters.Let's say the vehicleweighs1,000 kg and has good brakes and tires. In this case, the braking distance would be around 24 meters (4 x 20 x 0.25).Therefore,Stopping Distance =Perception Distance+ Reaction Distance + Braking Distance= 7.5 + 8 + 24= 39.5 meters.Now, let's calculate thedistancerequired to stop a vehicle traveling at a speed of 40 mph.Stopping Distance = Perception Distance + Reaction Distance + Braking Distance.As the length of the vehicle and the reaction time of the driver do not change, the only variable that changes in this equation is the braking distance.Therefore,Stopping Distance= Perception Distance + Reaction Distance + Braking Distance= 7.5 + 8 + (4 x 40 x 0.25)= 79 meters.Therefore, if the speed of avehicledoubles from 20 mph to 40 mph, the distance required to stop the vehicle increases by 4 times.Learn more aboutPerception Distancehere ;brainly.com/question/13034462#SPJ11...