All of these can be solved by separating complex figur into simpler one.Needed formulas are:Area of rectangle A=a*bArea of triangle A=a*h/2Area of paralelogram A= a*hQUESTION 1.When we connect points F and S we get a rectangle and a triangle.Dimensions of sides of a rectangle are a=9 and b=2.A=9*2=18For a triangle we need to take one side and it's height. Let's take side FS because it's easiest to find the height.a=9h=6A=9*6/2=27Tot+al area of a figure:A=18+27=45QUESTION 2.We connect point (1,1) with (1,-2) and (-6,1). This way we get a rectangle and three triangles.Rectangle:a=3b=4A=3*4=12Top right triangle:a=4h=3A=4*3/2=6Top left triangle:a=7h=2A=7*2/2=7Bottom left triangle:a=7h=3A=7*3/2=10.5Total area of a figure:A=12+6+7+10.5=35.5QUESTION 3.We connect points (-4,2) and (-1,3). This way we get a paralelogram and a rectangle.Paralelogram:a=6h=1A=6*1=6Rectangle:a=distance between (-4,2) and (-1,3) =b = distance between (-4,2) and (-2,-4) =A=a*b=Paralelogram:a=6h=1A=6*1=6Total area of a figure:A=+ 6QUESTION 4.We coonect missing side of a triangle. That side has a length of: 6in-3in=3in. Vertical side of triangle is: 13in-7in=6inArea:a=3h=6A=3*6/2=9Rectangle:a=7inb=6inA=7*6=42Total area of a figure:A=9+42=51...

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