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g To answer this question, you may reference the Metabolic Map. Select the steps of glycolysis in which ATP is produced. phosphoenolpyruvate → pyruvate phosphoenolpyruvate→pyruvate glucose → glucose 6‑phosphate glucose→glucose 6‑phosphate glyceraldehyde 3‑phosphate → 1,3‑bisphosphoglycerate glyceraldehyde 3‑phosphate→1,3‑bisphosphoglycerate 1,3‑bisphosphoglycerate → 3‑phosphoglycerate 1,3‑bisphosphoglycerate→3‑phosphoglycerate fructose 6‑phosphate → fructose 1,6‑bisphosphateSuppose 13 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the number of pyruvate molecules produced. Pi = Pyruvate =
g To answer this question, you may reference the Metabolic Map. Select the steps of glycolysis in which ATP is produced. phosphoenolpyruvate → pyruvate phosphoenolpyruvate→pyruvate glucose → glucose 6‑phosphate glucose→glucose 6‑phosphate glyceraldehyde 3‑phosphate → 1,3‑bisphosphoglycerate glyceraldehyde 3‑phosphate→1,3‑bisphosphoglycerate 1,3‑bisphosphoglycerate → 3‑phosphoglycerate 1,3‑bisphosphoglycerate→3‑phosphoglycerate fructose 6‑phosphate → fructose 1,6‑bisphosphateSuppose 13 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the number of pyruvate molecules produced. Pi = Pyruvate =
Answer:a) Total of ATP produced in glycolysis is equal to 2ATP produced:i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)ii) phosphoenolpyruvate→pyruvate (2 ATP are produced)b) 26 pyruvate molecules.Explanation:a) Glycolysis consists of two steps in which ATP is consumed and two steps in which ATP is released.ATP produced = 4ATP consumed = 2The total of ATP produced in glycolysis is equal to 2 (4-2)ATP produced:i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)ii) phosphoenolpyruvate → pyruvate (2 ATP are produced)b) In the sixth step of glycolysis, inorganic phosphate molecules are consumed:glyceraldehyde-3‑phosphate → 1,3‑bisphosphoglycerate2 pi are added in glycolysis. As each glucose molecule undergoes glycolysis, the pi required by the 13 glocosa molecules is 26 (13 * 2). Glycolysis of each glucose produces 3 pyruvates, so 13 glucose molecules will produce 26 pyruvate molecules....