Final answer:The pH of the resulting solution after adding 10.0 ml of 0.010 M HCl to 100.0 ml of water is calculated by finding the new concentration of H3O+ ions after dilution, which is used in the pH formula. The pH is determined to be approximately 3.04.Explanation:When a 10.0 ml portion of 0.010 M HCl is added to 100.0 ml of water, the concentration of HCl in the new solution can be calculated by the dilution formulaM1V1 = M2V2. Since HCl is a strong acid, it will dissociate completely in water, and the concentration of HCl will be equal to the concentration of H3O+ ions in the solution. The pH can then be calculated using the formula pH = -log[H3O+].Firstly, we calculate the moles of HCl initially present in the 10.0 ml portion:Moles of HCl = 0.010 moles/L * 0.010 L = 1.0 x 10^-4 molesAfter dilution in 100.0 ml (0.100 L) of water, the total volume becomes 110.0 ml or 0.110 L.The new concentration (M2) of the solution is :M2 = moles of HCl / total volume = 1.0 x 10^-4 moles / 0.110 L = 9.09 x 10^-4 MNow, we calculate the pH of the solution:pH = -log[9.09 x 10^-4] = 3.04Therefore, the pH of the resulting solution after adding 10.0 ml of 0.010 M HCl to 100.0 ml of water is approximately 3.04....

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