Theinscribed angleis half that of thearcit comprises. Themeasureof both theangleis 52°.How do we relate theinscribed angleand thearc?we know that theinscribed angleis half that of thearcit comprises.Here, thearcthat theinscribed anglescomprise is the same.2(3m+2)° = (4m+20)°by solving for m6m + 4 = 4m + 206m - 4m = 20 - 42m = 16m = 8To find themeasureof theangle(4m+20)°= 4(8) + 20 = 52°2(3m+2)° = 2(26) = 52Learn more aboutangleshere:brainly.com/question/27458498#SPJ2...

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