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Theperimeterandareaof each of the composite figure is:a.Area:138.6 mm²;Perimeter= 50.27 mm.b.Area:120.5 cm²;Perimeter= 42.7 cmc.Area:521.1 mm²;Perimeter:95.8 mmWhat is the Area of a Circle, Triangle, and a Rectangle?Areaof a circle = πr²Areaof a triangle = 1/2(base)(height).Areaof a rectangle = (length)(width).What is the Perimeter of a Composite Figure?Theperimeterof a composite figure = the sum of all lengths of the sides surrounding the composite figure.a. Theareaof the composite figure =areaof rectangle +areaof two semicirclesTwo semicircles = 1 circleAreaof the rectangle = (15)(5) = 75 mm²Areaof the two semicircles = πr² = π(4.5²) = 63.6 mm²Theareaof the composite figure = 75 + 63.6 = 138.6 mm².Perimeter= 5(2) + 4(3) + (perimeterof 1 circle)Perimeter= 5(2) + 4(3) + (2πr)Perimeter= 5(2) + 4(3) + (2π(4.5))Perimeter= 50.27 mm.b.Area=areaof triangle +areaof square +areaof half circleArea= 1/2(base)(height) + s² + 1/2(πr²)Base = 5 cmHeight = 7 cms = √(7² + 5²) = 8.6 cm [Pythagorean theorem]r = 8.6/2 = 4.3 cmArea= 1/2(5)(7) + 8.6² + 1/2(π(4.3²))Area= 120.5 cm²Perimeter= 5 + 7 + 8.6 + 8.6 + (perimeterof half circle)Perimeter= 5 + 7 + 8.6 + 8.6 + 1/2(2πr)Perimeter= 5 + 7 + 8.6 + 8.6 + (2π(4.3))Perimeter= 42.7 cmc.Area=areaof triangle +areaof rectangle +areaof half circleArea= 1/2(base)(height) + (length)(width) + 1/2(πr²)Base = 32 - 20 = 12 mmHeight = 14 mmLength = 20 mmWidth = 14 mmr = 1/2(20) = 10 mmArea= 1/2(12)(14) + (20)(14) + 1/2(π(10²))Area= 521.1 mm²Perimeter= 14 + 32 + hypotenuse of the triangle + (perimeterof half circle)Hypotenuse = √(12² + 14²) = 18.4 mmPerimeterof half circle = 1/2(2πr) = 1/2(2π(10)) = 31.4Perimeterof the composite figure = 14 + 32 + 18.4 + 31.4Perimeterof the composite figure = 95.8 mmLearn more about thearea of composite figureson:brainly.com/question/15981553#SPJ1...