Answered by AI, Verified by Human Experts
Assume you have 1 L of solution.Moles F- = M F- x L F- = (0.0610)(1) = 0.0610 moles F-0.0610 moles F- x(19.0 g F-/1mole F-) = 1.159 g F- in 1 L of solution1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g of solutionmass % F- = (g F- / g solution) x 100 = (1.159 / 1000) x 100= 0.1159%parts per million F- = mg F- /L = 1159 / 1 = 1159 ppm F-...