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Draw the product of the hydrogenation of 2‑butyne. Draw all hydrogen atoms. H3C−C≡C−CH3+2H2−→−Pt
Draw the product of the hydrogenation of 2‑butyne. Draw all hydrogen atoms. H3C−C≡C−CH3+2H2−→−Pt
The product of hydrogenation of butyne is H3C-CH=CH-CH3, and the product is butene as the product of the reaction would have adouble bond.Hydrogenationis the process of adding hydrogen to a compound or breaking the molecule's double or triple bond. The reaction between hydrogen gas and unsaturated organic compounds occurs in the presence of catalysts such as platinum, palladium, or nickel, and the reaction is termed hydrogenation. It is an exothermic reaction that typically takes place at high pressure and temperature. To draw the product of the hydrogenation of 2‑butyne, H3C−C≡C−CH3+2H2−→−Pt, and draw all hydrogen atoms, we must first comprehend the molecular structure of 2‑butyne. It is an alkyne with fourcarbonsin its structure. We can represent it in structural form as:H3C−C≡C−CH3We must first identify the carbon atoms involved in the triple bond and add two hydrogen atoms to each of the carbons.To know more aboutdouble bondvisit:brainly.com/question/29068102#SPJ11...