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Final answer:The reaction ofm-methylbenzenesulfonic acidwithchloromethaneand AlCl3 under Friedel-Crafts conditions leads to m-tolyl chloride as the major monoalkylation product.Explanation:The reaction of m-methylbenzenesulfonic acid with chloromethane andAlCl3is a type ofFriedel-Crafts alkylation, which is a method used to attach alkyl groups to an aromatic ring. In the reaction, AlCl3 works as a Lewis acid catalyst to facilitate thetransformationof m-methylbenzenesulfonic acid to a methylbenzene.Chloromethane(CH3Cl), a tetrahedral molecule, gives up its methyl group to the carbon atom in the aromatic ring. The resulting product is m-tolyl chloride, which is the major monoalkylation product from this reaction.Learn more aboutFriedel-Crafts Alkylationhere:brainly.com/question/32219561#SPJ11...