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Determine the net torque on the 2.0-m-long uniform beam

Determine the net torque on the 2.0-m-long uniform beam

Answer:14.42 NmExplanation:Assuming the figure attached and taking moment about point CTorque is the sum of all the torques about C.The distance between force pairs is half the beam length henceTorque = (56sin32) *(1m) +(65sin45) *(0m) -(52sin58) *(1m)Torque= 29.675 - 0 - 44.098 = 14.42 Nm anticlockwise...

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