Final answer:The molar mass of cesium phosphate is 493.70 g/mol. There are approximately 0.0316 moles of cesium phosphate and 0.0948 moles of cesium in 15.6 grams of cesium phosphate, which amounts to about 5.70 x 10^22 atoms of cesium.Explanation:To determine the molar mass of cesium phosphate, we must first know its chemical formula, which is Cs3PO4. This compound contains 3 cesium (Cs) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms. Using the periodic table, we can find the atomic masses for cesium (132.91 g/mol), phosphorus (30.97 g/mol), and oxygen (16.00 g/mol).The molar mass is calculated as follows: Molar mass = (3 x 132.91 g/mol) + (1 x 30.97 g/mol) + (4 x 16.00 g/mol) = 398.73 + 30.97 + 64.00 = 493.70 g/mol.To find out how many moles are in 15.6 grams of cesium phosphate, we use the formula: Moles = mass (g) / molar mass (g/mol). So, Moles = 15.6 g / 493.70 g/mol ≈ 0.0316 moles of cesium phosphate.Since there are 3 moles of cesium for every mole of cesium phosphate, the number of moles of cesium in 15.6 grams of cesium phosphate is 3 x 0.0316 moles ≈ 0.0948 moles of cesium.To determine the number of atoms of cesium, we multiply the moles of cesium by Avogadro's number (6.022 x 1023 atoms/mol): 0.0948 moles x 6.022 x 1023 atoms/mol ≈ 5.70 x 1022 atoms of cesium....

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