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Cu has two common oxidation states: +1 and +2. how could you explain an empirical formula of Cu2Cl3

Cu has two common oxidation states: +1 and +2. how could you explain an empirical formula of Cu2Cl3

Final answer:Theempirical formulaCu2Cl3 refers to a mixed valence compound, where two Cu atoms have a +1 oxidation state and one Cu atom has a +2 oxidation state, equating to the total charge of the Cl anions. This scenario can exist due to copper's characteristic of exhibiting more than one common oxidation state.Explanation:The empirical formulaCu2Cl3implies that this compound is a mixed valence compound, meaning copper (Cu) exists in more than one oxidation state within the same compound. To satisfy this empirical formula, two of the copper atoms have a +1 oxidation state and one copper atom has a +2 oxidation state. The sum of these oxidation states equates to the total charge of the three chloride (Cl) anions (3*-1=-3).This can also be referenced in atomic theory. For instance, in a brown compound with a copper-to-chlorine ratio of 1:2, the copper atom has a +1 oxidation state, and in a green compound with a copper-to-chlorine ratio of 1:1, the copper atom has a +2 oxidation state. The ratio of chlorine atoms is therefore 2 to 1.In simple ionic compounds such as Sodium chloride (NaCl), elements' oxidation numbers are numerically equivalent to ionic charges. But in our case, copper can exist with a +1 or +2 charge, and these combine with the chloride ions (Cl-) with a charge of -1 to form the mixed valence compound represented by the empirical formulaCu2Cl3.Learn more about Oxidation States here:brainly.com/question/31688257#SPJ1...

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